By Dr Antonio Gulli

ISBN-10: 1495330729

ISBN-13: 9781495330728

Bits is the second one of a chain of 25 Chapters dedicated to algorithms, challenge fixing, and C++ programming. This booklet is set low point bit programming

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**Additional info for A Collection of Bit Programming Interview Questions solved in C++**

**Sample text**

The code implements the following logic. (n & 1); } int multiply(int x, int y) { int res = 0; if (x < 0 && y < 0) { return multiply(negate(x), negate(y)); } if (x >= 0 && y < 0) { return multiply(y, x); } while (y > 0) { if (isEven(y)) { x <<= 1 ; y >>= 1; } else { res = add(res, x); y = add(y, -1); } } return res; } 13. Compute the two’s complement for a given integer Solution The two's complement of an n-bit number is the result of subtracting the number from . The two's complement system has the advantage that the arithmetic operations of addition, subtraction, and multiplication are identical to the ones defined for unsigned binary numbers.

Then the list is reversed and each element is prepended by a 1. As final step the two intermediate lists are juxtaposed to create the new list. This process is repeated until we generate. size(); i++) std::cout << gray[i] << std::endl; } 25. Represent unsigned integers with variable length encoding using the continuation bit Solution The key idea is to take a 64bit unsigned integer and represent it with a list of bytes. For each byte seven bits are used for storing the integers with variable length encoding.

Code Left as exercise. 12. Multiply two numbers without using arithmetic operators Solution Without loss of generality let’s assume that we multiply , and . The code is dealing with the case . While If y is even, we can multiply by 2 and divide by 2, otherwise we add to the result and we subtract 1 to . The code implements the following logic. (n & 1); } int multiply(int x, int y) { int res = 0; if (x < 0 && y < 0) { return multiply(negate(x), negate(y)); } if (x >= 0 && y < 0) { return multiply(y, x); } while (y > 0) { if (isEven(y)) { x <<= 1 ; y >>= 1; } else { res = add(res, x); y = add(y, -1); } } return res; } 13.

### A Collection of Bit Programming Interview Questions solved in C++ by Dr Antonio Gulli

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